(6+5i)/(3-2i)=0

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Solution for (6+5i)/(3-2i)=0 equation: 



(6+5i)/(3-2i)=0



Domain of the equation: (3-2i)!=0

We move all terms containing i to the left, all other terms to the right

-2i!=-3

i!=-3/-2

i!=1+1/2

i∈R



We add all the numbers together, and all the variables

(5i+6)/(-2i+3)=0

We multiply all the terms by the denominator


(5i+6)=0

We get rid of parentheses

5i+6=0

We move all terms containing i to the left, all other terms to the right

5i=-6

i=-6/5

i=-1+1/5

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