(6+v)(2v-5)=0

Solution for (6+v)(2v-5)=0 equation:

(6+v)(2v-5)=0

We add all the numbers together, and all the variables

(v+6)(2v-5)=0

We multiply parentheses ..

(+2v^2-5v+12v-30)=0

We get rid of parentheses

2v^2-5v+12v-30=0

We add all the numbers together, and all the variables

2v^2+7v-30=0

a = 2; b = 7; c = -30;
Δ = b2-4ac
Δ = 72-4·2·(-30)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*2}=\frac{-24}{4}
=-6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*2}=\frac{10}{4}
=2+1/2
$