(6+x)(9+x)=0

Solution for (6+x)(9+x)=0 equation:

(6+x)(9+x)=0

We add all the numbers together, and all the variables

(x+6)(x+9)=0

We multiply parentheses ..

(+x^2+9x+6x+54)=0

We get rid of parentheses

x^2+9x+6x+54=0

We add all the numbers together, and all the variables

x^2+15x+54=0

a = 1; b = 15; c = +54;
Δ = b2-4ac
Δ = 152-4·1·54
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*1}=\frac{-18}{2}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*1}=\frac{-12}{2}
=-6
$