(6+x)+z=6+(x+z)

Solution for (6+x)+z=6+(x+z) equation:

Simplifying
(6 + x) + z = 6 + (x + z)

Remove parenthesis around (6 + x)
6 + x + z = 6 + (x + z)

Remove parenthesis around (x + z)
6 + x + z = 6 + x + z

Add '-6' to each side of the equation.
6 + x + -6 + z = 6 + x + -6 + z

Reorder the terms:
6 + -6 + x + z = 6 + x + -6 + z

Combine like terms: 6 + -6 = 0
0 + x + z = 6 + x + -6 + z
x + z = 6 + x + -6 + z

Reorder the terms:
x + z = 6 + -6 + x + z

Combine like terms: 6 + -6 = 0
x + z = 0 + x + z
x + z = x + z

Add '-1x' to each side of the equation.
x + -1x + z = x + -1x + z

Combine like terms: x + -1x = 0
0 + z = x + -1x + z
z = x + -1x + z

Combine like terms: x + -1x = 0
z = 0 + z
z = z

Add '-1z' to each side of the equation.
z + -1z = z + -1z

Combine like terms: z + -1z = 0
0 = z + -1z

Combine like terms: z + -1z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.