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(6+x)/x=x/2+3
We move all terms to the left:
(6+x)/x-(x/2+3)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
(x+6)/x-(x/2+3)=0
We get rid of parentheses
(x+6)/x-x/2-3=0
We calculate fractions
(-1x^2)/2x+(2x+12)/2x-3=0
We multiply all the terms by the denominator
(-1x^2)+(2x+12)-3*2x=0
Wy multiply elements
(-1x^2)+(2x+12)-6x=0
We get rid of parentheses
-1x^2+2x-6x+12=0
We add all the numbers together, and all the variables
-1x^2-4x+12=0
a = -1; b = -4; c = +12;
Δ = b2-4ac
Δ = -42-4·(-1)·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8}{2*-1}=\frac{12}{-2} =-6 $
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