(6+y)(5y+4)=0

Solution for (6+y)(5y+4)=0 equation:

(6+y)(5y+4)=0

We add all the numbers together, and all the variables

(y+6)(5y+4)=0

We multiply parentheses ..

(+5y^2+4y+30y+24)=0

We get rid of parentheses

5y^2+4y+30y+24=0

We add all the numbers together, and all the variables

5y^2+34y+24=0

a = 5; b = 34; c = +24;
Δ = b2-4ac
Δ = 342-4·5·24
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-26}{2*5}=\frac{-60}{10}
=-6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+26}{2*5}=\frac{-8}{10}
=-4/5
$