(6+y)(5y-1)=0

Solution for (6+y)(5y-1)=0 equation:

(6+y)(5y-1)=0

We add all the numbers together, and all the variables

(y+6)(5y-1)=0

We multiply parentheses ..

(+5y^2-1y+30y-6)=0

We get rid of parentheses

5y^2-1y+30y-6=0

We add all the numbers together, and all the variables

5y^2+29y-6=0

a = 5; b = 29; c = -6;
Δ = b2-4ac
Δ = 292-4·5·(-6)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-31}{2*5}=\frac{-60}{10}
=-6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+31}{2*5}=\frac{2}{10}
=1/5
$