(6+y)(5y-3)=0

Solution for (6+y)(5y-3)=0 equation:

(6+y)(5y-3)=0

We add all the numbers together, and all the variables

(y+6)(5y-3)=0

We multiply parentheses ..

(+5y^2-3y+30y-18)=0

We get rid of parentheses

5y^2-3y+30y-18=0

We add all the numbers together, and all the variables

5y^2+27y-18=0

a = 5; b = 27; c = -18;
Δ = b2-4ac
Δ = 272-4·5·(-18)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-33}{2*5}=\frac{-60}{10}
=-6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+33}{2*5}=\frac{6}{10}
=3/5
$