(6+z)-(2z+4)=3

Solution for (6+z)-(2z+4)=3 equation:

Simplifying
(6 + z) + -1(2z + 4) = 3

Remove parenthesis around (6 + z)
6 + z + -1(2z + 4) = 3

Reorder the terms:
6 + z + -1(4 + 2z) = 3
6 + z + (4 * -1 + 2z * -1) = 3
6 + z + (-4 + -2z) = 3

Reorder the terms:
6 + -4 + z + -2z = 3

Combine like terms: 6 + -4 = 2
2 + z + -2z = 3

Combine like terms: z + -2z = -1z
2 + -1z = 3

Solving
2 + -1z = 3

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1z = 3 + -2

Combine like terms: 2 + -2 = 0
0 + -1z = 3 + -2
-1z = 3 + -2

Combine like terms: 3 + -2 = 1
-1z = 1

Divide each side by '-1'.
z = -1

Simplifying
z = -1