(6-(5/y+2))=-4/y-1

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Solution for (6-(5/y+2))=-4/y-1 equation: 



(6-(5/y+2))=-4/y-1

We move all terms to the left:

(6-(5/y+2))-(-4/y-1)=0



Domain of the equation: y+2))!=0

y∈R





Domain of the equation: y-1)!=0

y∈R



We get rid of parentheses

(6-(5/y+2))+4/y+1=0

We calculate fractions


((6-(5*y)/(y+2))*y)+4y/(y+2))*y)+1=0



We calculate terms in parentheses: +((6-(5*y)/(y+2))*y), so:

(6-(5*y)/(y+2))*y

We add all the numbers together, and all the variables

(6-(+5y)/(y+2))*y

We multiply all the terms by the denominator


(6-(+5y)



We calculate terms in parentheses: +(6-(+5y), so:

6-(+5y

determiningTheFunctionDomain
-(+5y+6

Back to the equation:

+(-(+5y+6)



We add all the numbers together, and all the variables

(-(5y+6)



We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6





We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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-(5y+6





We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6





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-(5y+6





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-(5y+6





We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6





We calculate terms in parentheses: +(-(5y+6), so:

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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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-(5y+6





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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

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We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6





We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6





We calculate terms in parentheses: +(-(5y+6), so:

-(5y+6



Back to the equation:

+((-(5y+6))



We multiply all the terms by the denominator


((-(5y+6))+4y=0

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