(6-+x)+(x+52)=102

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Solution for (6-+x)+(x+52)=102 equation: 



(6-+x)+(x+52)=102

We move all terms to the left:

(6-+x)+(x+52)-(102)=0

We add all the numbers together, and all the variables

(+x)+(x+52)-102=0

We get rid of parentheses

x+x+52-102=0

We add all the numbers together, and all the variables

2x-50=0

We move all terms containing x to the left, all other terms to the right

2x=50

x=50/2

x=25

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