(6-+x)+(x+52)=102

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Solution for (6-+x)+(x+52)=102 equation:



(6-+x)+(x+52)=102
We move all terms to the left:
(6-+x)+(x+52)-(102)=0
We add all the numbers together, and all the variables
(+x)+(x+52)-102=0
We get rid of parentheses
x+x+52-102=0
We add all the numbers together, and all the variables
2x-50=0
We move all terms containing x to the left, all other terms to the right
2x=50
x=50/2
x=25

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