(6-21+2y)=3(2y+10)

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Solution for (6-21+2y)=3(2y+10) equation:



(6-21+2y)=3(2y+10)
We move all terms to the left:
(6-21+2y)-(3(2y+10))=0
We add all the numbers together, and all the variables
(2y-15)-(3(2y+10))=0
We get rid of parentheses
2y-(3(2y+10))-15=0
We calculate terms in parentheses: -(3(2y+10)), so:
3(2y+10)
We multiply parentheses
6y+30
Back to the equation:
-(6y+30)
We get rid of parentheses
2y-6y-30-15=0
We add all the numbers together, and all the variables
-4y-45=0
We move all terms containing y to the left, all other terms to the right
-4y=45
y=45/-4
y=-11+1/4

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