(6-2c)-(2c+2)=0

Solution for (6-2c)-(2c+2)=0 equation:

Simplifying
(6 + -2c) + -1(2c + 2) = 0

Remove parenthesis around (6 + -2c)
6 + -2c + -1(2c + 2) = 0

Reorder the terms:
6 + -2c + -1(2 + 2c) = 0
6 + -2c + (2 * -1 + 2c * -1) = 0
6 + -2c + (-2 + -2c) = 0

Reorder the terms:
6 + -2 + -2c + -2c = 0

Combine like terms: 6 + -2 = 4
4 + -2c + -2c = 0

Combine like terms: -2c + -2c = -4c
4 + -4c = 0

Solving
4 + -4c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -4c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -4c = 0 + -4
-4c = 0 + -4

Combine like terms: 0 + -4 = -4
-4c = -4

Divide each side by '-4'.
c = 1

Simplifying
c = 1