(6-2c)3-3c=27

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Solution for (6-2c)3-3c=27 equation: 



(6-2c)3-3c=27

We move all terms to the left:

(6-2c)3-3c-(27)=0

We add all the numbers together, and all the variables

(-2c+6)3-3c-27=0

We add all the numbers together, and all the variables

-3c+(-2c+6)3-27=0

We multiply parentheses

-3c-6c+18-27=0

We add all the numbers together, and all the variables

-9c-9=0

We move all terms containing c to the left, all other terms to the right

-9c=9

c=9/-9

c=-1

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