(6-2i)(3-i)=0

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Solution for (6-2i)(3-i)=0 equation: 



(6-2i)(3-i)=0

We add all the numbers together, and all the variables

(-2i+6)(-1i+3)=0

We multiply parentheses ..

(+2i^2-6i-6i+18)=0

We get rid of parentheses

2i^2-6i-6i+18=0

We add all the numbers together, and all the variables

2i^2-12i+18=0

a = 2; b = -12; c = +18;
Δ = b2-4ac
Δ = -122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{12}{4}=3$

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