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(6-2i)(4-3i)=0
We add all the numbers together, and all the variables
(-2i+6)(-3i+4)=0
We multiply parentheses ..
(+6i^2-8i-18i+24)=0
We get rid of parentheses
6i^2-8i-18i+24=0
We add all the numbers together, and all the variables
6i^2-26i+24=0
a = 6; b = -26; c = +24;
Δ = b2-4ac
Δ = -262-4·6·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10}{2*6}=\frac{16}{12} =1+1/3 $$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10}{2*6}=\frac{36}{12} =3 $
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