(6-2k)/(k+3)=4

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Solution for (6-2k)/(k+3)=4 equation: 



(6-2k)/(k+3)=4

We move all terms to the left:

(6-2k)/(k+3)-(4)=0



Domain of the equation: (k+3)!=0

We move all terms containing k to the left, all other terms to the right

k!=-3

k∈R



We add all the numbers together, and all the variables

(-2k+6)/(k+3)-4=0

We multiply all the terms by the denominator


(-2k+6)-4*(k+3)=0

We multiply parentheses

(-2k+6)-4k-12=0

We get rid of parentheses

-2k-4k+6-12=0

We add all the numbers together, and all the variables

-6k-6=0

We move all terms containing k to the left, all other terms to the right

-6k=6

k=6/-6

k=-1

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