(6-3i)(2+i)=

Solution for (6-3i)(2+i)= equation:

Simplifying
(6 + -3i)(2 + i) = 0

Multiply (6 + -3i) * (2 + i)
(6(2 + i) + -3i * (2 + i)) = 0
((2 * 6 + i * 6) + -3i * (2 + i)) = 0
((12 + 6i) + -3i * (2 + i)) = 0
(12 + 6i + (2 * -3i + i * -3i)) = 0
(12 + 6i + (-6i + -3i2)) = 0

Combine like terms: 6i + -6i = 0
(12 + 0 + -3i2) = 0
(12 + -3i2) = 0

Solving
12 + -3i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -3i2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -3i2 = 0 + -12
-3i2 = 0 + -12

Combine like terms: 0 + -12 = -12
-3i2 = -12

Divide each side by '-3'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}