(6-3i)/(-8+4i)

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Solution for (6-3i)/(-8+4i) equation: 


D( i )

4*i-8 = 0

4*i-8 = 0

4*i-8 = 0

4*i-8 = 0 // + 8

4*i = 8 // : 4

i = 8/4

i = 2

i in (-oo:2) U (2:+oo)

(6-(3*i))/(4*i-8) = 0

(6-3*i)/(4*i-8) = 0

6-3*i = 0 // - 6

-3*i = -6 // : -3

i = -6/(-3)

i = 2

i in { 2} 

i belongs to the empty set

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