(6-3z)/5)=z

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Solution for (6-3z)/5)=z equation: 



(6-3z)/5)=z

We move all terms to the left:

(6-3z)/5)-(z)=0



Domain of the equation: 5)-z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(-3z+6)/5)-z=0

We multiply all the terms by the denominator


(-3z+6)=0

We get rid of parentheses

-3z+6=0

We move all terms containing z to the left, all other terms to the right

-3z=-6

z=-6/-3

z=+2

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