(6-8i)=(2+4i)

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Solution for (6-8i)=(2+4i) equation:



(6-8i)=(2+4i)
We move all terms to the left:
(6-8i)-((2+4i))=0
We add all the numbers together, and all the variables
(-8i+6)-((4i+2))=0
We get rid of parentheses
-8i-((4i+2))+6=0
We calculate terms in parentheses: -((4i+2)), so:
(4i+2)
We get rid of parentheses
4i+2
Back to the equation:
-(4i+2)
We get rid of parentheses
-8i-4i-2+6=0
We add all the numbers together, and all the variables
-12i+4=0
We move all terms containing i to the left, all other terms to the right
-12i=-4
i=-4/-12
i=1/3

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