(6-k)-(3k+1)=25

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Solution for (6-k)-(3k+1)=25 equation: 



(6-k)-(3k+1)=25

We move all terms to the left:

(6-k)-(3k+1)-(25)=0

We add all the numbers together, and all the variables

(-1k+6)-(3k+1)-25=0

We get rid of parentheses

-1k-3k+6-1-25=0

We add all the numbers together, and all the variables

-4k-20=0

We move all terms containing k to the left, all other terms to the right

-4k=20

k=20/-4

k=-5

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