(6-t)/(2t+9)=2

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Solution for (6-t)/(2t+9)=2 equation: 



(6-t)/(2t+9)=2

We move all terms to the left:

(6-t)/(2t+9)-(2)=0



Domain of the equation: (2t+9)!=0

We move all terms containing t to the left, all other terms to the right

2t!=-9

t!=-9/2

t!=-4+1/2

t∈R



We add all the numbers together, and all the variables

(-1t+6)/(2t+9)-2=0

We multiply all the terms by the denominator


(-1t+6)-2*(2t+9)=0

We multiply parentheses

(-1t+6)-4t-18=0

We get rid of parentheses

-1t-4t+6-18=0

We add all the numbers together, and all the variables

-5t-12=0

We move all terms containing t to the left, all other terms to the right

-5t=12

t=12/-5

t=-2+2/5

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