(6-v)(5v*8)=0

Solution for (6-v)(5v*8)=0 equation:

(6-v)(5v*8)=0

We add all the numbers together, and all the variables

(-1v+6)(+5v*8)=0

We multiply parentheses ..

(-40v^2+240v)=0

We get rid of parentheses

-40v^2+240v=0

a = -40; b = 240; c = 0;
Δ = b2-4ac
Δ = 2402-4·(-40)·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-240}{2*-40}=\frac{-480}{-80}
=+6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+240}{2*-40}=\frac{0}{-80}
=0
$