(6-v)(5v+8)=0

Solution for (6-v)(5v+8)=0 equation:

(6-v)(5v+8)=0

We add all the numbers together, and all the variables

(-1v+6)(5v+8)=0

We multiply parentheses ..

(-5v^2-8v+30v+48)=0

We get rid of parentheses

-5v^2-8v+30v+48=0

We add all the numbers together, and all the variables

-5v^2+22v+48=0

a = -5; b = 22; c = +48;
Δ = b2-4ac
Δ = 222-4·(-5)·48
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-38}{2*-5}=\frac{-60}{-10}
=+6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+38}{2*-5}=\frac{16}{-10}
=-1+3/5
$