(6-w)(4w+5)=0

Solution for (6-w)(4w+5)=0 equation:

(6-w)(4w+5)=0

We add all the numbers together, and all the variables

(-1w+6)(4w+5)=0

We multiply parentheses ..

(-4w^2-5w+24w+30)=0

We get rid of parentheses

-4w^2-5w+24w+30=0

We add all the numbers together, and all the variables

-4w^2+19w+30=0

a = -4; b = 19; c = +30;
Δ = b2-4ac
Δ = 192-4·(-4)·30
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-29}{2*-4}=\frac{-48}{-8}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+29}{2*-4}=\frac{10}{-8}
=-1+1/4
$