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(6-x)(x-1)=
We move all terms to the left:
(6-x)(x-1)-()=0
We add all the numbers together, and all the variables
(-1x+6)(x-1)-()=0
We add all the numbers together, and all the variables
(-1x+6)(x-1)=0
We multiply parentheses ..
(-1x^2+x+6x-6)=0
We get rid of parentheses
-1x^2+x+6x-6=0
We add all the numbers together, and all the variables
-1x^2+7x-6=0
a = -1; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·(-1)·(-6)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*-1}=\frac{-12}{-2} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*-1}=\frac{-2}{-2} =1 $
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