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(6-x)-8=-(2+x)
We move all terms to the left:
(6-x)-8-(-(2+x))=0
We add all the numbers together, and all the variables
(-1x+6)-(-(x+2))-8=0
We get rid of parentheses
-1x-(-(x+2))+6-8=0
We calculate terms in parentheses: -(-(x+2)), so:We add all the numbers together, and all the variables
-(x+2)
We get rid of parentheses
-x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
-(-1x-2)
-1x-(-1x-2)-2=0
We get rid of parentheses
-1x+1x+2-2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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