(6-y)(3y+8)=0

Solution for (6-y)(3y+8)=0 equation:

(6-y)(3y+8)=0

We add all the numbers together, and all the variables

(-1y+6)(3y+8)=0

We multiply parentheses ..

(-3y^2-8y+18y+48)=0

We get rid of parentheses

-3y^2-8y+18y+48=0

We add all the numbers together, and all the variables

-3y^2+10y+48=0

a = -3; b = 10; c = +48;
Δ = b2-4ac
Δ = 102-4·(-3)·48
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*-3}=\frac{-36}{-6}
=+6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*-3}=\frac{16}{-6}
=-2+2/3
$