(6/(3-12i))

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Solution for (6/(3-12i)) equation: 


D( i )

3-(12*i) = 0

3-(12*i) = 0

3-(12*i) = 0

3-12*i = 0

3-12*i = 0 // - 3

-12*i = -3 // : -12

i = -3/(-12)

i = 1/4

i in (-oo:1/4) U (1/4:+oo)

6/(3-(12*i)) = 0

6/(3-12*i) = 0

6 = 0

i belongs to the empty set

i belongs to the empty set

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