(6/(x+3))+(1/(x-3))=5

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Solution for (6/(x+3))+(1/(x-3))=5 equation: 


D( x )

x-3 = 0

x+3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

6/(x+3)+1/(x-3) = 5 // - 5

6/(x+3)+1/(x-3)-5 = 0

(6*(x-3))/((x+3)*(x-3))+(1*(x+3))/((x+3)*(x-3))+(-5*(x+3)*(x-3))/((x+3)*(x-3)) = 0

6*(x-3)+1*(x+3)-5*(x+3)*(x-3) = 0

7*x-5*x^2-15+45 = 0

7*x-5*x^2+30 = 0

7*x-5*x^2+30 = 0

7*x-5*x^2+30 = 0

DELTA = 7^2-(-5*4*30)

DELTA = 649

DELTA > 0

x = (649^(1/2)-7)/(-5*2) or x = (-649^(1/2)-7)/(-5*2)

x = (649^(1/2)-7)/(-10) or x = (649^(1/2)+7)/10

(x-((649^(1/2)-7)/(-10)))*(x-((649^(1/2)+7)/10)) = 0

((x-((649^(1/2)-7)/(-10)))*(x-((649^(1/2)+7)/10)))/((x+3)*(x-3)) = 0

((x-((649^(1/2)-7)/(-10)))*(x-((649^(1/2)+7)/10)))/((x+3)*(x-3)) = 0 // * (x+3)*(x-3)

(x-((649^(1/2)-7)/(-10)))*(x-((649^(1/2)+7)/10)) = 0

( x-((649^(1/2)+7)/10) )

x-((649^(1/2)+7)/10) = 0 // + (649^(1/2)+7)/10

x = (649^(1/2)+7)/10

( x-((649^(1/2)-7)/(-10)) )

x-((649^(1/2)-7)/(-10)) = 0 // + (649^(1/2)-7)/(-10)

x = (649^(1/2)-7)/(-10)

x in { (649^(1/2)+7)/10, (649^(1/2)-7)/(-10) }

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