(6/(x-40))+(5/(x+40))=11

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Solution for (6/(x-40))+(5/(x+40))=11 equation: 



(6/(x-40))+(5/(x+40))=11

We move all terms to the left:

(6/(x-40))+(5/(x+40))-(11)=0



Domain of the equation: (x-40))!=0

x∈R





Domain of the equation: (x+40))!=0

x∈R



We calculate fractions


(6x+240)/((x-40))*x+(5x-200)/((x-40))*x-11=0

We multiply all the terms by the denominator


(6x+240)+(5x-200)-11*((x-40))*x=0

We get rid of parentheses

6x+5x-11*((x-40))*x+240-200=0

We add all the numbers together, and all the variables

11x-11*((x-40))*x+40=0

We move all terms containing x to the left, all other terms to the right

11x-11*((x-40))*x=-40

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