(6/(x-9))-(9/(x-7))=-15

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Solution for (6/(x-9))-(9/(x-7))=-15 equation:


D( x )

x-7 = 0

x-9 = 0

x-7 = 0

x-7 = 0

x-7 = 0 // + 7

x = 7

x-9 = 0

x-9 = 0

x-9 = 0 // + 9

x = 9

x in (-oo:7) U (7:9) U (9:+oo)

6/(x-9)-(9/(x-7)) = -15 // + 15

6/(x-9)-(9/(x-7))+15 = 0

6/(x-9)-9*(x-7)^-1+15 = 0

6/(x-9)-9/(x-7)+15 = 0

(6*(x-7))/((x-9)*(x-7))+(-9*(x-9))/((x-9)*(x-7))+(15*(x-9)*(x-7))/((x-9)*(x-7)) = 0

6*(x-7)-9*(x-9)+15*(x-9)*(x-7) = 0

15*x^2-3*x-240*x+39+945 = 0

15*x^2-243*x+984 = 0

15*x^2-243*x+984 = 0

3*(5*x^2-81*x+328) = 0

5*x^2-81*x+328 = 0

DELTA = (-81)^2-(4*5*328)

DELTA = 1

DELTA > 0

x = (1^(1/2)+81)/(2*5) or x = (81-1^(1/2))/(2*5)

x = 41/5 or x = 8

3*(x-8)*(x-41/5) = 0

(3*(x-8)*(x-41/5))/((x-9)*(x-7)) = 0

(3*(x-8)*(x-41/5))/((x-9)*(x-7)) = 0 // * (x-9)*(x-7)

3*(x-8)*(x-41/5) = 0

( 3 )

3 = 0

x belongs to the empty set

( x-41/5 )

x-41/5 = 0 // + 41/5

x = 41/5

( x-8 )

x-8 = 0 // + 8

x = 8

x in { 41/5, 8 }

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