(6/15)ln(x)-7ln(y)=ln(a)

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Solution for (6/15)ln(x)-7ln(y)=ln(a) equation:


D( x )

x <= 0

x <= 0

x in (0:+oo)

(6/15)*ln(x)-(7*ln(y)) = ln(a) // - ln(a)

(6/15)*ln(x)-(7*ln(y))-ln(a) = 0

(6/15)*ln(x)-7*ln(y)-ln(a) = 0

t_1 = ln(x)

t_2 = ln(y)

t_3 = -ln(a)

(6/15)*t_1-7*ln(y)-ln(a) = 0

(2*t_1)/5-7*t_2+t_3 = 0

(2*t_1)/5+(-7*5*t_2)/5+(5*t_3)/5 = 0

2*t_1-7*5*t_2+5*t_3 = 0

2*t_1-35*t_2+5*t_3 = 0

(2*t_1-35*t_2+5*t_3)/5 = 0

(2*t_1-35*t_2+5*t_3)/5 = 0 // * 5

2*t_1-35*t_2+5*t_3 = 0

2*t_1-35*t_2+5*t_3 = 0 // - 5*t_3-35*t_2

2*t_1 = -(5*t_3-35*t_2) // : 2

t_1 = (-(5*t_3-35*t_2))/2

t_1 = (-(5*(-ln(a))-35*ln(y)))/2

ln(x) = (-(5*(-ln(a))-35*ln(y)))/2

ln(x) = ln(e^((-(5*(-ln(a))-35*ln(y)))/2))

x = e^((-(5*(-ln(a))-35*ln(y)))/2)

x = e^((-(-35*ln(y)-5*ln(a)))/2)

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