(6/2x-3)=(4/2x+5)

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Solution for (6/2x-3)=(4/2x+5) equation: 



(6/2x-3)=(4/2x+5)

We move all terms to the left:

(6/2x-3)-((4/2x+5))=0



Domain of the equation: 2x-3)!=0

x∈R





Domain of the equation: 2x+5))!=0

x∈R



We get rid of parentheses

6/2x-((4/2x+5))-3=0

We calculate fractions


12x/4x^2+(-((4*2x)/4x^2-3=0

We add all the numbers together, and all the variables

12x/4x^2+(-((+4*2x)/4x^2-3=0

We calculate fractions

We do not support expression: x^4

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