(6/5)(5+2g)=-18

Solution for (6/5)(5+2g)=-18 equation:

(6/5)(5+2g)=-18

We move all terms to the left:

(6/5)(5+2g)-(-18)=0


Domain of the equation: 5)(5+2g)!=0

g∈R


We add all the numbers together, and all the variables

(+6/5)(2g+5)-(-18)=0

We add all the numbers together, and all the variables

(+6/5)(2g+5)+18=0

We multiply parentheses ..

(+12g^2+6/5*5)+18=0

We multiply all the terms by the denominator


(+12g^2+6+18*5*5)=0

We get rid of parentheses

12g^2+6+18*5*5=0

We add all the numbers together, and all the variables

12g^2+456=0

a = 12; b = 0; c = +456;
Δ = b2-4ac
Δ = 02-4·12·456
Δ = -21888
Delta is less than zero, so there is no solution for the equation