(6/5)(y+1)=(7/5)y

Solution for (6/5)(y+1)=(7/5)y equation:

(6/5)(y+1)=(7/5)y

We move all terms to the left:

(6/5)(y+1)-((7/5)y)=0


Domain of the equation: 5)(y+1)!=0

y∈R



Domain of the equation: 5)y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+6/5)(y+1)-((+7/5)y)=0

We multiply parentheses ..

(+6y^2+6/5*1)-((+7/5)y)=0

We calculate fractions


(6y^2+30y)/25y^2+()/25y^2=0

We multiply all the terms by the denominator


(6y^2+30y)+()=0

We add all the numbers together, and all the variables

(6y^2+30y)=0

We get rid of parentheses

6y^2+30y=0

a = 6; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·6·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*6}=\frac{-60}{12}
=-5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*6}=\frac{0}{12}
=0
$