(6/5)k-(k-3)=-39

Solution for (6/5)k-(k-3)=-39 equation:

(6/5)k-(k-3)=-39

We move all terms to the left:

(6/5)k-(k-3)-(-39)=0


Domain of the equation: 5)k!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(+6/5)k-(k-3)-(-39)=0

We add all the numbers together, and all the variables

(+6/5)k-(k-3)+39=0

We multiply parentheses

6k^2-(k-3)+39=0

We get rid of parentheses

6k^2-k+3+39=0

We add all the numbers together, and all the variables

6k^2-1k+42=0

a = 6; b = -1; c = +42;
Δ = b2-4ac
Δ = -12-4·6·42
Δ = -1007
Delta is less than zero, so there is no solution for the equation