(6/5)k-(k/3)=-39

Solution for (6/5)k-(k/3)=-39 equation:

(6/5)k-(k/3)=-39

We move all terms to the left:

(6/5)k-(k/3)-(-39)=0


Domain of the equation: 5)k!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(+6/5)k-(+k/3)-(-39)=0

We add all the numbers together, and all the variables

(+6/5)k-(+k/3)+39=0

We multiply parentheses

6k^2-(+k/3)+39=0

We get rid of parentheses

6k^2-k/3+39=0

We multiply all the terms by the denominator


6k^2*3-k+39*3=0

We add all the numbers together, and all the variables

6k^2*3-1k+117=0

Wy multiply elements

18k^2-1k+117=0

a = 18; b = -1; c = +117;
Δ = b2-4ac
Δ = -12-4·18·117
Δ = -8423
Delta is less than zero, so there is no solution for the equation