(6/5)x+10=(2x-13)

Solution for (6/5)x+10=(2x-13) equation:

(6/5)x+10=(2x-13)

We move all terms to the left:

(6/5)x+10-((2x-13))=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+6/5)x-((2x-13))+10=0

We multiply parentheses

6x^2-((2x-13))+10=0


We calculate terms in parentheses: -((2x-13)), so:

(2x-13)

We get rid of parentheses

2x-13

Back to the equation:

-(2x-13)


We get rid of parentheses

6x^2-2x+13+10=0

We add all the numbers together, and all the variables

6x^2-2x+23=0

a = 6; b = -2; c = +23;
Δ = b2-4ac
Δ = -22-4·6·23
Δ = -548
Delta is less than zero, so there is no solution for the equation