(6/5)y+1=(7/5)y

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Solution for (6/5)y+1=(7/5)y equation:



(6/5)y+1=(7/5)y
We move all terms to the left:
(6/5)y+1-((7/5)y)=0
Domain of the equation: 5)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 5)y)!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+6/5)y-((+7/5)y)+1=0
We multiply parentheses
6y^2-((+7/5)y)+1=0
We multiply all the terms by the denominator
6y^2*5)y)-((+1*5)y)+7=0
We add all the numbers together, and all the variables
6y^2*5)y)-(5y)+7=0
We add all the numbers together, and all the variables
6y^2*5)y)-5y+7=0
Wy multiply elements
30y^3=0
We do not support eypression: y^3

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