(6/7)v-(5/3)=-(5/2)

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Solution for (6/7)v-(5/3)=-(5/2) equation: 



(6/7)v-(5/3)=-(5/2)

We move all terms to the left:

(6/7)v-(5/3)-(-(5/2))=0



Domain of the equation: 7)v!=0

v!=0/1

v!=0

v∈R



We add all the numbers together, and all the variables

(+6/7)v-(+5/3)-(-(+5/2))=0

We multiply parentheses

6v^2-(+5/3)-(-(+5/2))=0

We get rid of parentheses

6v^2-5/3-(-(+5/2))=0

We calculate fractions


6v^2+()/()+()/()=0

We add all the numbers together, and all the variables

6v^2+2=0

a = 6; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·6·2
Δ = -48
Delta is less than zero, so there is no solution for the equation

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