(6/7)x+3=1/7x+8

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Solution for (6/7)x+3=1/7x+8 equation:



(6/7)x+3=1/7x+8
We move all terms to the left:
(6/7)x+3-(1/7x+8)=0
Domain of the equation: 7)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 7x+8)!=0
x∈R
We add all the numbers together, and all the variables
(+6/7)x-(1/7x+8)+3=0
We multiply parentheses
6x^2-(1/7x+8)+3=0
We get rid of parentheses
6x^2-1/7x-8+3=0
We multiply all the terms by the denominator
6x^2*7x-8*7x+3*7x-1=0
Wy multiply elements
42x^3-56x+21x-1=0
We do not support expression: x^3

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