(6/m-4)-(2/m+4)=(60/m2-16)

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Solution for (6/m-4)-(2/m+4)=(60/m2-16) equation:


D( m )

m^2 = 0

m = 0

m^2 = 0

m^2 = 0

1*m^2 = 0 // : 1

m^2 = 0

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

6/m-(2/m)-4-4 = 60/(m^2)-16 // - 60/(m^2)-16

6/m-(2/m)-(60/(m^2))-4-4+16 = 0

6/m-2*m^-1-60*m^-2-4-4+16 = 0

4*m^-1-60*m^-2+8 = 0

t_1 = m^-1

4*t_1^1-60*t_1^2+8 = 0

4*t_1-60*t_1^2+8 = 0

DELTA = 4^2-(-60*4*8)

DELTA = 1936

DELTA > 0

t_1 = (1936^(1/2)-4)/(-60*2) or t_1 = (-1936^(1/2)-4)/(-60*2)

t_1 = -1/3 or t_1 = 2/5

t_1 = -1/3

m^-1+1/3 = 0

1*m^-1 = -1/3 // : 1

m^-1 = -1/3

-1 < 0

1/(m^1) = -1/3 // * m^1

1 = -1/3*m^1 // : -1/3

-3 = m^1

m = -3

t_1 = 2/5

m^-1-2/5 = 0

1*m^-1 = 2/5 // : 1

m^-1 = 2/5

-1 < 0

1/(m^1) = 2/5 // * m^1

1 = 2/5*m^1 // : 2/5

5/2 = m^1

m = 5/2

m in { -3, 5/2 }

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