(6/v+1)+(3/3v+3)

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Solution for (6/v+1)+(3/3v+3) equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

(3/3)*v+6/v+1+3 = 0

1*v^1+6*v^-1+4*v^0 = 0

(1*v^2+4*v^1+6*v^0)/(v^1) = 0 // * v^2

v^1*(1*v^2+4*v^1+6*v^0) = 0

v^1

v^2+4*v+6 = 0

v^2+4*v+6 = 0

DELTA = 4^2-(1*4*6)

DELTA = -8

DELTA < 0

v in { } 

v belongs to the empty set

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