(6/x)+(1/7)=(5/3x)

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Solution for (6/x)+(1/7)=(5/3x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x+1/7 = (5/3)*x // - (5/3)*x

6/x-((5/3)*x)+1/7 = 0

(-5/3)*x+6/x+1/7 = 0

6*x^-1-5/3*x^1+1/7*x^0 = 0

(1/7*x^1-5/3*x^2+6*x^0)/(x^1) = 0 // * x^2

x^1*(1/7*x^1-5/3*x^2+6*x^0) = 0

x^1

(-5/3)*x^2+(1/7)*x+6 = 0

(-5/3)*x^2+(1/7)*x+6 = 0

DELTA = (1/7)^2-(4*6*(-5/3))

DELTA = 1961/49

DELTA > 0

x = ((1961/49)^(1/2)-(1/7))/(2*(-5/3)) or x = (-(1/7)-(1961/49)^(1/2))/(2*(-5/3))

x = -3/10*((1961/49)^(1/2)-1/7) or x = 3/10*((1961/49)^(1/2)+1/7)

x in { -3/10*((1961/49)^(1/2)-1/7), 3/10*((1961/49)^(1/2)+1/7)} 

x in { -3/10*((1961/49)^(1/2)-1/7), 3/10*((1961/49)^(1/2)+1/7) }

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