(6/x)=(3/2x)+9

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Solution for (6/x)=(3/2x)+9 equation:



(6/x)=(3/2x)+9
We move all terms to the left:
(6/x)-((3/2x)+9)=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2x)+9)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+6/x)-((+3/2x)+9)=0
We get rid of parentheses
6/x-((+3/2x)+9)=0
We calculate fractions
12x/2x^2+(-((+3*x)/2x^2=0
We add all the numbers together, and all the variables
12x/2x^2+(-((+3x)/2x^2=0
We multiply all the terms by the denominator
12x+(-((+3x)=0
We calculate terms in parentheses: +(-((+3x), so:
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