(6/x+1)+(9/2x+2)

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Solution for (6/x+1)+(9/2x+2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(9/2)*x+6/x+1+2 = 0

9/2*x^1+6*x^-1+3*x^0 = 0

(9/2*x^2+3*x^1+6*x^0)/(x^1) = 0 // * x^2

x^1*(9/2*x^2+3*x^1+6*x^0) = 0

x^1

(9/2)*x^2+3*x+6 = 0

(9/2)*x^2+3*x+6 = 0

DELTA = 3^2-(4*6*(9/2))

DELTA = -99

DELTA < 0

x in { } 

x belongs to the empty set

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