(6/x-1)+(3/x-1)=(1/x-1)+2

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Solution for (6/x-1)+(3/x-1)=(1/x-1)+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x+3/x-1-1 = 1/x-1+2 // - 1/x-1+2

6/x+3/x-(1/x)-2-1-1+1 = 0

6/x+3/x-x^-1-2-1-1+1 = 0

8*x^-1 = 3 // : 8

x^-1 = 3/8

-1 < 0

1/(x^1) = 3/8 // * x^1

1 = 3/8*x^1 // : 3/8

8/3 = x^1

x = 8/3

x = 8/3

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