(6/x-4)/(2x-3)=0

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Solution for (6/x-4)/(2x-3)=0 equation: 


D( x )

x = 0

2*x-3 = 0

x = 0

x = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in (-oo:0) U (0:3/2) U (3/2:+oo)

(6/x-4)/(2*x-3) = 0

(6*x^-1-4)/(2*x-3) = 0

6*x^-1 = 4 // : 6

x^-1 = 2/3

-1 < 0

1/(x^1) = 2/3 // * x^1

1 = 2/3*x^1 // : 2/3

3/2 = x^1

x = 3/2

x in { 3/2} 

x belongs to the empty set

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